Am primit următoarele soluţii corecte:

1.

Zoltan Szabo:

2016=9 * 8 * 7 * 6! / 5! * 4 / 3 / 2 * 1 + 0

2016= -9 * 8 * 7 - 6!+ 5! * 4! + 3!! / 2 * 1 + 0

2016=9 * 8 * 7 * (6 - 5) * 4 + 3 * 2 * 1 * 0

2016=9 * 8 * 7 * (6 - 5 + 4 - 3 + 2 * 1 + 0)

2016=9 * 8 * 7 * (6 - 5 + 4 - 3 + 2) * 1 + 0

2016=SQRT(9! * 8 * 7 * 6 / 5! * 4 + 3 - 2 - 1 - 0)

2016=9! * 8! / 7! / 6! / (5 - 4 + 3 - 2 + 1 * 0)

2016=SQRT(SQRT(9! * 8!) * 7! * 6) / 5 / (4 + 3 - 2 + 1 + 0)

2016=9! * 8! / 7! / 6! /(-5! / 4! + 3! + 2! - 1!) * 0!

2016=(9 * 8 * 7) ^{6 - 5} * 4 * 3 ^ (2 * 1 * 0)

Aurel Ionescu:

2016=9*8*7!/6/5*4/3/2+1*0

Claudiu Emil Man:

2016=9*8+7+6^5/4-3*2-1

Camelia Muşetescu:

2016 = 9!! + 8!! + 7!! +6! - 5! - 4! + 3! - 2! +1! + 0!

Ştefan Gaţachiu: 2016=9×8×7×(6-5+4-3+2×1+0)

 

2. 

Aurel Ionescu, Zoltan Szabo, Camelia Muşetescu, Claudiu Emil ManŞtefan Gaţachiu:  2016=1²-2²+…-62²+63²

 

3.

Aurel Ionescu, Claudiu Drăgan:  2016=2⁵*7*9

Ady Nicolae:  2016 = 9! / (6² x 5)

Szabo Zoltan, Claudiu Emil Man:  2016=9*8*7*4

Camelia Muşetescu, Ştefan Gaţachiu:  2016 = 2 * 7! / 5

 

Marius Alecsadru: 2016 = 2⁵ * 3² * 7 = 2³⁺² * 3² * (2² + 3) = 2²⁺³⁺² * 3² + 2³⁺² *3³ , asadar se utilizeaza 3 operatori si numai 2 cifre !