Am primit următoarele soluţii corecte:
1.
Zoltan Szabo:
2016=9 * 8 * 7 * 6! / 5! * 4 / 3 / 2 * 1 + 0
2016= -9 * 8 * 7 - 6!+ 5! * 4! + 3!! / 2 * 1 + 0
2016=9 * 8 * 7 * (6 - 5) * 4 + 3 * 2 * 1 * 0
2016=9 * 8 * 7 * (6 - 5 + 4 - 3 + 2 * 1 + 0)
2016=9 * 8 * 7 * (6 - 5 + 4 - 3 + 2) * 1 + 0
2016=SQRT(9! * 8 * 7 * 6 / 5! * 4 + 3 - 2 - 1 - 0)
2016=9! * 8! / 7! / 6! / (5 - 4 + 3 - 2 + 1 * 0)
2016=SQRT(SQRT(9! * 8!) * 7! * 6) / 5 / (4 + 3 - 2 + 1 + 0)
2016=9! * 8! / 7! / 6! /(-5! / 4! + 3! + 2! - 1!) * 0!
2016=(9 * 8 * 7) 6 - 5 * 4 * 3 ^ (2 * 1 * 0)
Aurel Ionescu:
2016=9*8*7!/6/5*4/3/2+1*0
Claudiu Emil Man:
2016=9*8+7+6^5/4-3*2-1
Camelia Muşetescu:
2016 = 9!! + 8!! + 7!! +6! - 5! - 4! + 3! - 2! +1! + 0!
Ştefan Gaţachiu: 2016=9×8×7×(6-5+4-3+2×1+0)
2.
Aurel Ionescu, Zoltan Szabo, Camelia Muşetescu, Claudiu Emil ManŞtefan Gaţachiu: 2016=12-22+…-622+632
3.
Aurel Ionescu, Claudiu Drăgan: 2016=25*7*9
Ady Nicolae: 2016 = 9! / (62 x 5)
Szabo Zoltan, Claudiu Emil Man: 2016=9*8*7*4
Camelia Muşetescu, Ştefan Gaţachiu: 2016 = 2 * 7! / 5
Marius Alecsadru: 2016 = 25 * 32 * 7 = 23+2 * 32 * (22 + 3) = 22+3+2 * 32 + 23+2 *33 , asadar se utilizeaza 3 operatori si numai 2 cifre !